2019 tamuctf - Reversing - 042

문제 : Cheers for actual assembly!

 

디게 간단하다. 코드안에서 숫자를 뺴내면 된다

 

movb $65, -16(%rbp)

movb $53, -15(%rbp)

movb $53, -14(%rbp)

movb $51, -13(%rbp)

movb $77, -12(%rbp)

movb $98, -11(%rbp)

movb $49, -10(%rbp)

movb $89, -9(%rbp)

 

 

65 -> A

53 -> 5

53 -> 5

51 -> 3

77 -> M

98 -> b

49 -> 1

89 -> Y

 

A553Mb1y

 

답 : gigem{A553Mb1Y}